In the reaction,$H_2C = CH_2 \xrightarrow{\text{cold alkaline } KMnO_4} (A)$. Product $A$ is :

  • A
    Ethylene glycol
  • B
    Acetic acid
  • C
    Ethane
  • D
    Butyric acid

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$CH_3-C(CH_3)(Br)-CH(CH_3)_2 \xrightarrow[\Delta]{EtOH} (A)$
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